How do I prove that [math]frac{sin190° cos 225° tan 390° }{cos 100° sin 135°} = -left(frac{1}{3}right)^{frac{1}{2}}?[/math]
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How do I prove that [math]frac{sin190° cos 225° tan 390° }{cos 100° sin 135°} = -left(frac{1}{3}right)^{frac{1}{2}}?[/math]
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